tighter: unary minus or inverse/transpose?

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mspiegel's picture
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Joined: 07/31/2009

I don't happen to have Mx 1.0 installed on this machine. Which operator binds tighter, unary minus or inverse/transpose? I don't know what is the "correct" answer, but I figure someone could just try -A~ and see which operator is applied first.

mspiegel's picture
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Joined: 07/31/2009
Umm, I believe that was a

Umm, I believe that was a dumb question. (-A)~ = (-I * A)~ = A~ * (-I)~ = A~ * -I = -(A~). Right? Similar argument for transpose.

Steve's picture
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Joined: 07/30/2009
Yep.

Yep.